8m^2+17m+2=0

Solution for 8m^2+17m+2=0 equation:

8m^2+17m+2=0

a = 8; b = 17; c = +2;
Δ = b2-4ac
Δ = 172-4·8·2
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-15}{2*8}=\frac{-32}{16}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+15}{2*8}=\frac{-2}{16}
=-1/8
$